shell----
just
posted @ 2009年3月20日 07:31
in linux
, 1136 阅读
1 最简单的shell脚本：
vi first.sh
在里面输入
ls -l
保存退出
最简单的脚本 现在它没有执行权限
要执行 chmod a+x first.sh 付给它执行权限
然后 ./first.sh 即可执行
2------------------------
下面继续修改 接受输入
first.sh:
#接受输入 然后再输出
echo "please enter your name:"
read fname
echo $fname
echo "please enter your name:"
read fname
echo $fname
保存退出。
运行 ./first.sh
-------------------------------------------
3 继续
#接受输入 然后再输出
echo "please enter your name:"
read fname
echo $fname
s=xxx
echo $s
echo "please enter your name:"
read fname
echo $fname
s=xxx
echo $s
4
echo `date`
date命令用反引号，就是esc下面的那个键
5
expr 4 + 5 #注意 4 + 5 之间有空格
输出 9
expr 4+5 # 没有空格
输出 4+5
-----
echo $((4+5))
输出 9
6---------------
read score #读入分数
if [$score -lt 80 ] #如果小于80
then
echo "wrong !!!"
elif [ $score -ge 80 -a $score -lt 9 ] # 大于等于80 小于90
then
echo "good "
else
echo "very good"
fi
if [$score -lt 80 ] #如果小于80
then
echo "wrong !!!"
elif [ $score -ge 80 -a $score -lt 9 ] # 大于等于80 小于90
then
echo "good "
else
echo "very good"
fi
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